Fill in the blank : For the circuit shown below, solve for gmVoD = 20 VRo = 4.7 k2Ipss = 10 mAVas(om)= -4 VCout= 100 µFCn = 0.1 µF+2.15 VR= 22 k2Vn =300 mVp-pRs =1 k2RG= 1.5 MNCs = 100 µFO 3.75mSO 2.313mSO 5mSO 1.069mS

The Solution is given below The answer is option B that is 2.313 ms

Fill in the blank : For the circuit shown below, solve for gm VoD = 20 V Ro = 4.7 k2 Ipss = 10 mA Vas(off) = -4 V Cout = 100 µF Cin = 0.1 µF +2.15 V R= 22 k2 Va = 300 mVp-p Rs = 1 k2 %3D Re = 1.5 MS Cs = 100 µF O 3.75mS O 2.313mS O 5mS O 1.069mS

Fill in the blank : For the circuit shown below, solve for gm VoD = 20 V Ro = 4.7 k2 Ipss = 10 mA Vas(off) = -4 V Cout = 100 µF Cin = 0.1 µF +2.15 V R= 22 k2 Va = 300 mVp-p Rs = 1 k2 %3D Re = 1.5 MS Cs = 100 µF O 3.75mS O 2.313mS O 5mS O 1.069mS

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Fill in the blank : For the circuit shown below, solve for gm
VoD = 20 V
Ro = 4.7 k2
Ipss = 10 mA
Vas(om)
= -4 V
Cout
= 100 µF
Cn = 0.1 µF
+2.15 V
R= 22 k2
Vn =
300 mVp-p
Rs =
1 k2
RG
= 1.5 MN
Cs = 100 µF
O 3.75mS
O 2.313mS
O 5mS
O 1.069mS

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