The following impedances are connected in parallel in the electric circuit. Z, = 4+ 9j Z2 = 4 – 1 Z3 = 2 – 9j If the equivalent impedance of the circuit is given by Z where 1 1 Z1 Z,' Z3 1 -= - +- i. Find the equivalent impedance and express it in polar form. ii. Find the current I flowing in the circuit when a 230 V AC voltage source is connected to it, where the current is given by. V I iii. Deduce the square apparent power P, = 1*z? of the circuit using de Moivre's theorem where necessary. iv. Due to a malfunction in the power supply, it was found that the square apparent power P, of the circuit dropped by half. Assuming that the impedance Z remained constant, calculate the current I flowing in the circuit during the malfunction using the equation given in part ii. Use de Moivre's theorem in your calculations where necessary. > IN

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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The following impedances are connected in parallel in the electric circuit.
Z1 = 4 + 9j
Z2 = 4 – 1
Z3 = 2 – 9j
If the equivalent impedance of the circuit is given by Z where
1 1
1
+
+
Z1' Z2' Z3
= -
i.
Find the equivalent impedance and express it in polar form.
ii.
Find the current I flowing in the circuit when a 230 V AC voltage source is connected to it,
where the current is given by.
V
I =-
iii.
Deduce the square apparent power P, = 1*z² of the circuit using de Moivre's theorem
where necessary.
iv.
Due to a malfunction in the power supply, it was found that the square apparent power P,
of the circuit dropped by half. Assuming that the impedance Z remained constant,
calculate the current I flowing in the circuit during the malfunction using the equation
given in part ii. Use de Moivre's theorem in your calculations where necessary.
Transcribed Image Text:The following impedances are connected in parallel in the electric circuit. Z1 = 4 + 9j Z2 = 4 – 1 Z3 = 2 – 9j If the equivalent impedance of the circuit is given by Z where 1 1 1 + + Z1' Z2' Z3 = - i. Find the equivalent impedance and express it in polar form. ii. Find the current I flowing in the circuit when a 230 V AC voltage source is connected to it, where the current is given by. V I =- iii. Deduce the square apparent power P, = 1*z² of the circuit using de Moivre's theorem where necessary. iv. Due to a malfunction in the power supply, it was found that the square apparent power P, of the circuit dropped by half. Assuming that the impedance Z remained constant, calculate the current I flowing in the circuit during the malfunction using the equation given in part ii. Use de Moivre's theorem in your calculations where necessary.
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