Fill in the table below and answer the questions using these formulas. pH = -log [H*] pOH = -log [OH] Kw= [H*][OH-] Kw = 1.0x 10-14 [H*]= antilog(-pH) [OH]= antilog(-pOH) pH + pOH = 14 [H*] [OH ] pH pOH Acid/Base 2.0 x 10-7 6.9 x 10-3 9.5 5.92 4.8 2.09 x 10-11 5.14 x 10-7 4.13 x 10-7 7.90

Fill in the table below and answer the questions using these formulas. pH = -log [H] pOH = -log [OH] Kw= [H][OH-] Kw = 1.0x 10-14 [H]= antilog(-pH) [OH]= antilog(-pOH) pH + pOH = 14 [H] [OH ] pH pOH Acid/Base 2.0 x 10-7 6.9 x 10-3 9.5 5.92 4.8 2.09 x 10-11 5.14 x 10-7 4.13 x 10-7 7.90

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter3: Bonding: General Concepts

Section: Chapter Questions

Problem 114E

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