Can you help me find a test statistics and the P value Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6211 patients treated with this drug, 158 developed the adversereaction of nausea. Use a 0.01 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction?O A. Ho: p+0.03H,: p=0.03B. Ho p=0.03H,: p#0.03O C. Ho: p= 0.03H,: p<0.03O D. Ho p=0.03H,: p>0.03Identify the test statistic for this hypothesis test.The test statistic for this hypothesis test is.(Round to two decimal places as needed.)Enter your answer in the answer box and then click Check Answer.partsremainingClear AllCheck Answer

Name: Can you help me find a test statistics and the P value Consider a drug
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Description: Can you help me find a test statistics and the P value Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6211 patients treated with this drug, 158 developed the adversereaction of nausea. Use a 0.

The sample proportion is, p^=xn=1586211=0.0254 The sample proportion is 0.02544. The test statistic…

Answered: find a test statistics and the P value

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter11: Data Analysis And Probability

Section: Chapter Questions

Problem 8CR

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Can you help me find a test statistics and the P value

Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6211 patients treated with this drug, 158 developed the adverse
reaction of nausea. Use a 0.01 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction?
O A. Ho: p+0.03
H,: p=0.03
B. Ho p=0.03
H,: p#0.03
O C. Ho: p= 0.03
H,: p<0.03
O D. Ho p=0.03
H,: p>0.03
Identify the test statistic for this hypothesis test.
The test statistic for this hypothesis test is.
(Round to two decimal places as needed.)
Enter your answer in the answer box and then click Check Answer.
parts
remaining
Clear All
Check Answer

Expert Solution

Step 1

The sample proportion is,

$\begin{array}{rcl} \hat{p} & = & \frac{x}{n} \\ = & \frac{158}{6211} \\ = & 0.0254 \end{array}$

The sample proportion is 0.02544.

The test statistic is,

$\begin{array}{rcl} z & = & \frac{\hat{p} - p}{\sqrt{\frac{p (1 - p)}{n}}} \\ = & \frac{0.02544 - 0.03}{\sqrt{\frac{0.03 (1 - 0.03)}{6211}}} \\ = & \frac{- 0.00456}{0.002164} \\ = & - 2.11 \end{array}$

Thus, the test statistic is -2.11.

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