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Find all real zeros of the function f (y) = 4y^ 3 +3y ^2 +8y +6

Question

Find all real zeros of the function f (y) = 4y^ 3 +3y ^2 +8y +6

check_circleAnswer
Step 1

Find the all real zeros of the given function.

f(y) 4y 3y+8y +6
In order to find the zeros of the function, find the value of y such that
4y 3y8y6 0
4у' + 3у? +8у+6-0
(4y' +3y2)+(8y +6) = 0
у (4у+3) +2(4y+3) -0
(4y+3)(y +2)-0
4y 3 0 or y 2 = 0
3
or y +2 = 0
4
y
help_outline

Image Transcriptionclose

f(y) 4y 3y+8y +6 In order to find the zeros of the function, find the value of y such that 4y 3y8y6 0 4у' + 3у? +8у+6-0 (4y' +3y2)+(8y +6) = 0 у (4у+3) +2(4y+3) -0 (4y+3)(y +2)-0 4y 3 0 or y 2 = 0 3 or y +2 = 0 4 y

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Step 2

Find the solution of the equation&...

y2 0
y2-2
y = 2
Thus, the solution of the equation y +2 0 are +2i
3
Therefore, the solution of the equation 4y +3y2 +8y+6=0 are 2i and --.
4
help_outline

Image Transcriptionclose

y2 0 y2-2 y = 2 Thus, the solution of the equation y +2 0 are +2i 3 Therefore, the solution of the equation 4y +3y2 +8y+6=0 are 2i and --. 4

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Tagged in

Math

Algebra

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