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Find an equation of the normal line to the surface given implicitly by z = sin(xy) at the point (5,-1, -1³). Lütfen birini seçin: T √√3 -ty=-1+t, z = -- - t.teR 2 2 bz = -¹/t₁y = −1+ t.2 = √3 t. - t.teR 2 x = -1/2+²t₁y = -t, z = -1 t.teR √3 dz=-t₁y=+=--t.teR 3 √3 ²z=-1-t₁y = -1 +2=-1-tte R 2 >2 √3

Find an equation of the normal line to the surface given implicitly by z = sin(xy) at the point (5,-1, -1³). Lütfen birini seçin: T √√3 -ty=-1+t, z = -- - t.teR 2 2 bz = -¹/t₁y = −1+ t.2 = √3 t. - t.teR 2 x = -1/2+²t₁y = -t, z = -1 t.teR √3 dz=-t₁y=+=--t.teR 3 √3 ²z=-1-t₁y = -1 +2=-1-tte R 2 >2 √3

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find an equation of the normal line to the surface given implicitly by z = sin(ry) at the point (,-1, -). %3D Lütfen birini seçin: a. = -t. y = -1+ t,z = -t,te R b. I. V3 -t.teR -. y = -1+t.z= CI = - +t.y =; -t.z= -1 V3 t,t e R d.I = 6 - t. y = - + +t.2 = - V3 t,te R z = --t.y = -1+t.2= -1 - V3 -t,teR 2= - -
Transcribed Image Text:Find an equation of the normal line to the surface given implicitly by z = sin(ry) at the point (,-1, -). %3D Lütfen birini seçin: a. = -t. y = -1+ t,z = -t,te R b. I. V3 -t.teR -. y = -1+t.z= CI = - +t.y =; -t.z= -1 V3 t,t e R d.I = 6 - t. y = - + +t.2 = - V3 t,te R z = --t.y = -1+t.2= -1 - V3 -t,teR 2= - -
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