Find az for the function : x? sin ( y3 ) + x e3z - cos ( z? ) = 3 y - 6 z + 8 .A dz 2 x sin (3y ) + 3e dx — 6 - 3хе3г 2 z sin (2z) .B - 2 z sin ( z² ) a z a x +6 - 3 x e3z 2x cos ( y ) + e3z .C 2 x sin (y3) + e3z - 2 z sin (z²) dz 6 — 3хез2 .D 3y²x?cos ( y3) –3 — 6 — 3хез2 dz 2 z sin (z2) II II N

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 15T
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Question
az
for the function :
a x
Find
x2 sin ( y ) + x e3z - cos ( z? ) = 3 y - 6 z + 8
.A
dz
2 x sin (3y ) + 3e
dx
6 — 3хе32
2 z sin (2z)
.B
- 2 z sin ( z² )
a z
a x
+6 - 3 x e3z
3
2x cos ( y³ ) + e3z
.C
2 x sin (y3) + e3z
- 2 z sin (z²)
dz
Əx
6 — Зхез2
.D
3y²x?cos ( y³) –
37 - 2 z sin ( z²)
dz
dx
— 6 — 3хез2
II
II
II
N
Transcribed Image Text:az for the function : a x Find x2 sin ( y ) + x e3z - cos ( z? ) = 3 y - 6 z + 8 .A dz 2 x sin (3y ) + 3e dx 6 — 3хе32 2 z sin (2z) .B - 2 z sin ( z² ) a z a x +6 - 3 x e3z 3 2x cos ( y³ ) + e3z .C 2 x sin (y3) + e3z - 2 z sin (z²) dz Əx 6 — Зхез2 .D 3y²x?cos ( y³) – 37 - 2 z sin ( z²) dz dx — 6 — 3хез2 II II II N
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