Find ∆Hf for Al2O3 using the following data 2 Al + 3/2 O2 ----> Al2O3 H2 + ½ O2 ------------> H2O ∆H1 = –286 kJ/mol 2 Al + 6 H+ -------------> 2 Al3+ + 3 H2 ∆H2 = –1050 kJ/mol Al2O3 + 6 H+ -----------> 2 Al3+ + 3 H2O ∆H3 = –238 kJ/mol NOTE: I calculated #5 to be ∆Hf =-1670 kJ/mol. 6. Using the value calculated in #5, find the temperature change expected when 0.100 g Al reacts with oxygen if the calorimeter used has a heat capacity of 420 J/°C.
Find ∆Hf for Al2O3 using the following data 2 Al + 3/2 O2 ----> Al2O3 H2 + ½ O2 ------------> H2O ∆H1 = –286 kJ/mol 2 Al + 6 H+ -------------> 2 Al3+ + 3 H2 ∆H2 = –1050 kJ/mol Al2O3 + 6 H+ -----------> 2 Al3+ + 3 H2O ∆H3 = –238 kJ/mol NOTE: I calculated #5 to be ∆Hf =-1670 kJ/mol. 6. Using the value calculated in #5, find the temperature change expected when 0.100 g Al reacts with oxygen if the calorimeter used has a heat capacity of 420 J/°C.
Chapter17: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 55E: For the reaction at 298 K, 2NO2(g)N2O4(g) the values of H and S are 58.03 kJ and 176.6 J/K,...
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1. Find ∆Hf for Al2O3 using the following data 2 Al + 3/2 O2 ----> Al2O3
H2 + ½ O2 ------------> H2O ∆H1 = –286 kJ/mol
2 Al + 6 H+ -------------> 2 Al3+ + 3 H2 ∆H2 = –1050 kJ/mol
Al2O3 + 6 H+ -----------> 2 Al3+ + 3 H2O ∆H3 = –238 kJ/mol
NOTE: I calculated #5 to be ∆Hf =-1670 kJ/mol.
6. Using the value calculated in #5, find the temperature change expected when 0.100 g Al reacts with oxygen if the calorimeter used has a heat capacity of 420 J/°C.
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