Find fF(x), the Fourier expansion of the function f(x) = -1 -1 Σ (1+(-1)"+1) cos(nr2) n=1 fF(x) = 6+ (1+ (-1)"+1) cos(nrx) n=1 ff(x) = 3+ (1 – (–1)") sin(nTx) %3D n=1 ff(x) = S (1 – (–1)") sin(nTE) n=1

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