Find its capacitance. Strategy Use Equation 26.3. Solution From Equation 26.3, we find the following. c- (2.15 x 10-ª m² 1.62 x 10- m - (8.85 x 10-12 C/N - m²) PF Exercise 26.1 Hints: Getting Started | I'm Stuck If the plate separation is increased to 6.60 mm, find the capacitance. C- PF

Physics for Scientists and Engineers with Modern Physics
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Chapter25: Capacitance And Dielectrics
Section: Chapter Questions
Problem 12P: (a) Find the equivalent capacitance between points a and b for the group of capacitors connected as...
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Problem A parallel-plate capacitor has an area A = 2.15 x 104 m2 and a plate separation d = 1.62 mm.
Find its capacitance.
Strategy Use Equation 26.3.
Solution
From Equation 26.3, we find the following.
= (8.85 x 10-12 C² /N•m³)
(2.15 x 10–4 m²
1.62 x 10-3 m
C3=
pF
Exercise 26.1
Hints: Getting Started | I'm Stuck
If the plate separation is increased to 6.60 mm, find the capacitance.
C-
Transcribed Image Text:Problem A parallel-plate capacitor has an area A = 2.15 x 104 m2 and a plate separation d = 1.62 mm. Find its capacitance. Strategy Use Equation 26.3. Solution From Equation 26.3, we find the following. = (8.85 x 10-12 C² /N•m³) (2.15 x 10–4 m² 1.62 x 10-3 m C3= pF Exercise 26.1 Hints: Getting Started | I'm Stuck If the plate separation is increased to 6.60 mm, find the capacitance. C-
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