Find RT. I5, 11. 12. 13 R1 R2 R3 -14V 7k2 10k2 10kn RT = Is = %3D 12 = %3D 13 =
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Q: A В C R,=12002 V;=7V 1, = 5.9mA R = 5602 V =6.06V I = 10.6mA %3D I=16.4mA E= 11.7V Red + D E Green -…
A: Redrawing the circuit by marking the current in each branch as shown below:
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Q: + VR - a.) VR 15 ohms IT b.) Vc 450µF + c.) IT Vc 110V/f Xc 7 ohms d.) f e.) ZT
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Q: with (R2 = 10kN, Rc = 3.9k, RE = 1kN), also assume that V cc = 10 volt, VBE = 0.7 and B = 150. %3D…
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Q: Customer Prob 4 10 Given step-down transformer T1 has N1/N2 = 10 and vab = 170COS(377t) a) Find…
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Q: Refer to the circuit below. Using supperposition, The current Iz is given by: R1 24 N E2 48 V E 54 V…
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Q: Given that R1=7463, R2=2495, R3=7420., Find Rth between the terminals a-b for the circuit shown…
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Q: Given: R = 4.2 N R2 = 8.4 N %3D R3 = 7.7 N Using Kirchhoff's laws, and utilizing the direction in…
A: To Find currents in different branches, Nodal analysis (KCL) is best suitable due to its less…
Q: Example4/ Draw the voltage Vm as a function of time when Z, = Ro = 500 for figure shown www 500 ww…
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Q: R1 I G2 Vs = R3 G4 Sources Value Passives Value R1 G2 R3 G4 Vs 5 V 250 ms 200 ms Find Iz 1A
A: first we will convert all elements into resistors by using resistance = 1conductance and we will use…
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Q: 2 *100u 21 DS9 +V V Gs9 + 0.5 = 0.72 V. 0.004 2*100u 0.5 = -0.72 V. DS10 V GS10 +V, %3D 0.004 (j) We…
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Q: Prob 4 Customer 10 Given step-dowWn transformer T1 has N1/N2 = 10 and vab = 170Cos(377t) a) Find…
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Q: 4. Given R1=4 Q,R2=5 0,R3=8 Q,R4%3D10 0,R5=2 Q, and Is=2 A, solve for the node voltages shown. R1 R2…
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Q: P2: Derive in afig then Find It fer Li=lg=L3a15H Lege For the circuit shown +M13%=DAM31=2H %3D…
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Q: Making use of the following where VG1 =D 3mV, VG2 = 2mV, Gm 100 m mho Calculate : %3D %D a. Vo1 b.…
A: Given data: gm=100 m-mho VG1=3 mV VG2=2 mV RS=20 kΩ RD=50 kΩ
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Q: Circuits for • Solve the folbwing quanti ties listed./ RI R2 R2 R4 Given E= 150 VDC RI = 2.7 KA…
A: Solution: Given, R1=2.7 kΩ=2700 ΩR2=3.3 KΩ=3300 ΩR3=6000 ΩR4=3000 Ωand, E=150 V from the circuit,…
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Q: Consider the circuit below. 36 kO I - 6 µF V2 'T+ V. 18 kNs |14 12 kOs 36 mH V3 Va 10 mH Ic 8 µF 10…
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Q: 2. Given the circuit, R5 R3 2 kn R1 3 kn 1 kn + V1 R28 kn R427 kn R526 kn 111 V Applied Voltage…
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Q: For the circuit given in the figure, Vs=10V, R1 =7 Ohm, R2= 6 Ohm, R3=5 Ohm R4=4 Ohm. For this…
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Q: Rr = [{(R, || R2 || R6) + R3} || R4] + R5 23.005kN = [{(10kN || 8kN || 1kN) + 4.7kN} || 6.6kN] + R5…
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Q: Determine V o for the network of Figure. D1 o V 10 V D2 | R 1 k2 O V Attached your SOLUTION HERE…
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A: Given thatVGS=VP3Drain currentID=IDSS1-132ID=12m1-132ID=5.3mA
Q: R1 R2 12 15 V3 25 V4 V5 18 15 R4 R3 'RS 20 30. 10 R6 R7 A 30 50 V2 R8 5, 14 V1 R9 R10 15 8
A: For loop 1; By using KVL 12−15I1+18−20(I1−I2)−30(I1−I3)−30I1=0 −95I1+20I2+30I3=−30 ...(1)…
Q: I. -13R1 + 14R2 – 1,R6 + E = 0 II. 4R2 – I6R4 + I5R3 = 0 R3 III. I3R1 + I5R3 = I½R5| IV. -12R5 –…
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Q: 13 14 12 ET. R2 R3 R4 RT R1 - P2 0.78 P3 1.031 P4 0.931 PT P1 0.704 IT 0.0143 12,3,4 13,4 m
A: Given circuit shown
Q: Use Kirchhoffs Law to determine i,, iz, and iz in the circuit below R1 10 il RS 20 30 7V R3 S10 R2…
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Q: P1.20, Compute the load current, i, by the Thevenin equivalent method n the circuit of Figure. %3D V…
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Q: Where: R1= 9 Q, R2= 10O N, R3= 5 Q, R4= 8 Q, R5= 5 Q, R6= 50 E= 12 V, I = 6 A Using Nodal analysis,…
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Q: Q #3 Solve for VA, I1 & I2 of the circuit shown 9V 5kn VA 12 4ka 2ks -9L
A: Circuit is given as,
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- just please full the blank from this video below Electromagnetic Spectrum1) https://youtu.be/1bpmI3wdqW82) https://youtu.be/FWCN_uI5ygY3) https://youtu.be/ZaXm6wau-jc4) https://youtu.be/W2VVoKArRcQ5) https://youtu.be/GxAyRJjCAsQFor the circuit shown in Figure P1.76, solve for i s. What types of sources are present in this circuit?moduleMSX-83fromBPsolarisusedinthefollowingconfigurationtomakeaPVarray: •4modulesinseries •2strings(of4modulesinseries)inparallel TheelectriccharacteristicsatSTCaregivenbelow: Maximumpower(Pmax)=83W Short-circuitcurrent(Isc)=5.27A VoltageatPmax(Vmp)=17.1V Open-circuitvoltage(Voc)=21.2V CurrentatPmax(Imp)=4.85A WhatwillbetheelectriccharacteristicsofthePVarray?
- A pure element is connected across an AC signal. CH1 and CH2 measures the voltage and current respectively: CH1 (Yellow) Settings: CH2 (Blue) Settings: Volts/Div: 50V Current Probe Ratio: 100 mV/mA Time/Div: 5ms Volts/Div: 20V Probe Settings: X1 Time/Div: 5ms Probe Settings: X1 If ?? (distance between two ‘purple’ cursors) is 5ms, determine:a. CH2 Peak Currentb. CH2 RMS Currentc. Impedance of the pure elementd. Type of load. If reactive, indicate the values of inductance or capacitanceSince R1=18.10Kohm, R2=67.58Kohm, RC= 1.08Kohm, RE= 3.23Kohm, VCC=14.00V, Beta=241.00 in the circuit given in the figure, calculate the IC current by doing a complete analysis. When performing your operations, 2 steps will be taken after the point. choose the closest one from the stylish ones according to the +/-10% margin of error. There is only 1 correct answer to the question.A load that draws 12A is located 275 feet from its 240VDC source. It is supplied by aluminum conductors with a diameter of .092 inches operating at 75°C. What is the resistance of one conductor?
- Given: D1: GaAs, Rb = 2 ohms, Rr = 375 kilo-ohmsD2: GaAs, Rb = 3 ohms, Rr = 200 kilo-ohmsD3: GaAs, Rb = 5 ohms, Rr = 150 kilo-ohms Determine ID1, ID2, ID3 using 3rd approximation please do not answer if this question is posted for 25 mins nowAn ac resistance is higher than a dc resistance. True FalseCOURSE: HIGH VOLTAGE TECHNIQUE In an insulating environment consisting of insulating oil (Ɛr1=12.5) and porcelain (Ɛr2=2.5), the electric field enters the porcelain environment through the oil at an angle of 50 relative to the normal of the border surface. Since the field strength is 87 kV/cm in oil environment, calculate the electric field strength in the porcelain environment, the tangent and normal components of the electric field strength in both environments. PLEASE MAKE A DETAILED SOLUTION!
- Identify the characteristics of AC and DC voltage. Runs at a higher temperature Answer 1Choose...DCAC More dangerous to transfer Answer 2Choose...DCAC Easy to produce Answer 3Choose...DCAC Easier to transform voltages Answer 4Choose...DCAC Voltage remains at a constant value Answer 5Choose...DCAC Cheaper to produceFind io(t) if vs(t)=400sin2500tV. Suppose that io(t)=I0cos(ωt+ϕ), where −180∘<ϕ≤180∘. Determine the values of I0, ω, and ϕ. Express your answers using three significant figures separated by commas. Enter I0 in amperes, ω in radians per second, and ϕ in degrees.Electrical Engineering _ Energy Conversion Systems pls findthe question by using computer line. pls find fast.