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Rr = [{(R, || R2 || R6) + R3} || R4] + R5 23.005kN = [{(10kN || 8kN || 1kN) + 4.7kN} || 6.6kN] + R5 23.005kN = 3.005kN + R5 R5 = 20kN Total current,IT %3D 20V 23.005kN

Rr = [{(R, || R2 || R6) + R3} || R4] + R5 23.005kN = [{(10kN || 8kN || 1kN) + 4.7kN} || 6.6kN] + R5 23.005kN = 3.005kN + R5 R5 = 20kN Total current,IT %3D 20V 23.005kN

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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How did we get 3.005 please explain step-by-step
To calculate R5, equation of the total resistance (RT) of the circuit need to be be as: Rp = [{(R1 || R2 || Rg) + R3} | R4] + R5 [{(10kN || 8kN || 1kN) + 4.7kN} || 6.6kN] + R5 3.005kN + R5 23.005kN 23.005kN = 20kN R5 Total current, I7 = 20V 23.005kN
Transcribed Image Text:To calculate R5, equation of the total resistance (RT) of the circuit need to be be as: Rp = [{(R1 || R2 || Rg) + R3} | R4] + R5 [{(10kN || 8kN || 1kN) + 4.7kN} || 6.6kN] + R5 3.005kN + R5 23.005kN 23.005kN = 20kN R5 Total current, I7 = 20V 23.005kN
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