Question
Asked Nov 30, 2019
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Find the coordinates of the vertex for the parabola defined by the given quadratic function

f(x)=-x2-8x-9

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Expert Answer

Step 1

Consider the given equation of the parabola.

y x8x-9
-(1)
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y x8x-9 -(1)

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Step 2

The standard quadratic equation form, y = ax2 + bx + c

b
Vertex: x
2a
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b Vertex: x 2a

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Step 3

Therefore, the vertex of the ...

-8
x
2(-1)
x = -4
On putting the value of x in equation (1), we get
y (-4)8x-4-9
y 16+32-9
y = 7
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-8 x 2(-1) x = -4 On putting the value of x in equation (1), we get y (-4)8x-4-9 y 16+32-9 y = 7

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