Find the differential equation of the following function (х — Зу + 2)dx + 3(х + Зу— 4)dy %3D0 х-1 а. In[(x — 1)2 — 9(у — 1)?] — Аrctan = C 3(y-1) х-1 b. In[(x — 1)? + 9(у — 1)2]— Arctan = C (у-1) х-1 с. In[(x — 1)2 + 9(у — 1)?]— Arctan — С 3(у-1) d. In[(x — 1)2 +9(у— 1)2]—Arctan У-1 = C 3(х-1)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Find the differential equation of the following function (x - 3y + 2)dx + 3(x + 3y – 4)dy = 0

Find the differential equation of the following function
(х — Зу + 2)dx + 3(х + 3у — 4)dy — 0
x-1
а. In[(x — 1)? — 9(у — 1)?] — Аrctan
= C
3 (у-1)
х-1
b. In[(x — 1)? +9(у — 1)?] — Arctan
(y-1)
х-1
с. In[(x — 1)2 + 9(у — 1)2] — Arctan
= C
3(y-1)
d. In[(x — 1)? +9(у — 1)?] — Arctan
y-1
= C
3(х-1)
Transcribed Image Text:Find the differential equation of the following function (х — Зу + 2)dx + 3(х + 3у — 4)dy — 0 x-1 а. In[(x — 1)? — 9(у — 1)?] — Аrctan = C 3 (у-1) х-1 b. In[(x — 1)? +9(у — 1)?] — Arctan (y-1) х-1 с. In[(x — 1)2 + 9(у — 1)2] — Arctan = C 3(y-1) d. In[(x — 1)? +9(у — 1)?] — Arctan y-1 = C 3(х-1)
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