Question

Asked Jan 25, 2020

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Find the distance from the point (3, -4, 2) to the

a. xy-plane

b. yz-plane

c.xz-plane.

Step 1

a) Distance of (3, -4, 2) from xy plane:

On xy plane , z=0.

So, This point is 2 units away from the z=0. Because it has z=2

Answer: 2

Step 2

b) Distance of (3, -4, 2) from yz plane:

On yz plane , x=0.

So, This point...

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