Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: (contour integral E with rightwards harpoon with barb upwards on top) * (stack d A with rightwards harpoon with barb upwards on top) = ___________ /epsilon0 EA = ___________ / epsilon0 Since, its the line charge we use the area of a cylinder surrounding the line charge E*2pi ___________ L= ___________ / epsilon0 But all the charged get enclosed by the cylinder area, so qenc = Q Deriving, we get: E = (1/2(pi*epsilon0))*(___________ /rL) **see picture for the symbols used

Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: (contour integral E with rightwards harpoon with barb upwards on top) * (stack d A with rightwards harpoon with barb upwards on top) = _____ /epsilon0 EA = _ / epsilon0 Since, its the line charge we use the area of a cylinder surrounding the line charge E2pi _ L= _ / epsilon0 But all the charged get enclosed by the cylinder area, so qenc = Q Deriving, we get: E = (1/2(piepsilon0))*(_______ /rL) **see picture for the symbols used

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 65P: A long cylinder of aluminum of radius R meters is charged so that it has a uniform charge per unit...

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One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

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Find the electric field everywhere of an infinite uniform line charge with total charge Q.

Sol.

Using Gauss's Law:

(contour integral E with rightwards harpoon with barb upwards on top) * (stack d A with rightwards harpoon with barb upwards on top) = ___________ /epsilon₀

EA = ___________ / epsilon₀

Since, its the line charge we use the area of a cylinder surrounding the line charge

E*2^pi ___________ L= ___________ / epsilon₀

But all the charged get enclosed by the cylinder area, so

q_enc = Q

Deriving, we get: E = (1/2^{(pi*epsilon0)})*(___________ /rL)

**see picture for the symbols used

Find the electric field everywhere of an infinite uniform line charge with total charge Q.
Sol.
Using Gauss's Law:
EA =
Since, its the line charge we use the area of a cylinder surrounding the line charge
E*2T
But all the charged get enclosed by the cylinder area, so
denc -Q
Deriving, we get:
E- (1/2 TEO )*(
IrL)

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