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Find the equation of a line passing through point (3,-2) and
perpendicular to the line 2x + 3y + 4-0.
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Find the equation of a line passing through point (3,-2) and perpendicular to the line 2x + 3y + 4-0.

Expert Answer

Step 1

To find slope of the given line, we express it in a standard form, y = mx + c, we get:

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Step 2

Comparing the equation obtained above with the standard form, we get:

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Step 3

If m1 and m2 are the slopes of two lines that are perpendicular to each other, then we have, m1* m2 = -1. Here, let m1 be the slope obtained above, then m1 = -2/3. Solving for m2,...

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