Question
Asked Dec 17, 2019
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Find the equation of the axis of symmetry and the coordinates of the vertex of the parabola given by the equation.

x = y2 − 2y − 4
axis of symmetry      
 
 
vertex    
(x, y) = 
 
 
 
 


Sketch the graph.

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Expert Answer

Step 1

Consider the following given equation,

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x= y² - 2y – 4 At vertex, slope = 0 dx :0 dy ( -2y-4)=0 2y- 2 = 0 y =1 x=(1)° – 2(1)– 4 x= -5 Vertex =(-5,1)

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Step 2

Axis of symmetry will be along the vertex point and will be parallel to x-axis as the equation is a quadratic in terms of ‘y’. Therefore, axis of symmetry will be given by, y = 1

Step 3

To sketch the graph, calculate the intercepts of...

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Vertex = (-5,1) x-intercept: x=-4 y-intercept: 2+(-2)* – 4-1-(-4) 2-1 2+/20 2 =1+ 5,1-5

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Tagged in

Math

Algebra

Equations and In-equations