Find the expected value E(X) of the following data. Round your answer to one decimal place. x −6 −5 −4 −3 −2 P(X=x) 0.10 0.20 0.10 0.20 0.4
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Find the
| x | −6 | −5 | −4 | −3 | −2 |
|---|---|---|---|---|---|
| P(X=x) | 0.10 | 0.20 | 0.10 | 0.20 | 0.4 |
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- Consider the following data find the expected value E(X).Round your answer to one decimal place.Find the expected value E(X) of the following data.Round your answer to one decimal place.Consider the following data: x −4 −3 −2 −1 0 P(X=x) 0.1 0.1 0.1 0.3 0.4 Find the expected value E(X). Round your answer to one decimal place.
- Following equation is given Y= (x+5)^3 + x^2 +10x What is the expected value of Y? Given E{X} = 4 E{x^2} = 9 E{x^3} =12 Explain Briefly(still referring to the table) For a one-unit increase in X1 for observations with X2=0, what is the expected change in Y? What about for observations with X2=1? a. -0.778 b. 0.344 c. 0.055 d. -0.723Find the expected value E(X)�(�) of the following data. Round your answer to one decimal place. x −6−6 −5−5 −4−4 −3−3 −2−2 P(X=x)�(�=�) 0.30.3 0.10.1 0.10.1 0.10.1 0.40.4
- Consider the following data: x 11 22 33 44 55 P(X=x)P(X=x) 0.10.1 0.20.2 0.30.3 0.20.2 0.20.2 Step 1 of 5: Find the expected value E(X)E(X). Round your answer to one decimal place.A life insurance company sells a term insurance policy to a 21-year-old male that pays $100,000 if the insured dies within the next 5 years. The company collects a premium of $250 each year as payment for the insurance. The amount X that the company earns on this policy is $250 per year, less the $100,000 that it must pay if the insured dies. From mortality tables, the expected value of X, denoted E(X) or ?, is $304 and the standard deviation of X, denoted SD(X) or ?, is $9002. Question 1. The risk of insuring one person's life is reduced if we insure many people. Suppose an insurance company insures two 21-year-old males and that their ages at death are independent. If X1 and X2 are what the company earns from the two insurance policies, the insurance company's average income on the two policies is Z = 1/2 (X1 + X2) Find the expected value E(Z) and the standard deviation SD(Z) of the random variable Z. (Note: since the ages at death are independent, Var(X1+X2)=Var(X1)+Var(X2)) 2. If…What is the expected value of y if f(y) = 6y + 0.5 and 0≤y≤0.05? (Round your answer to six decimal places.)