Find the flux of the vector field F across the surface S in the indicated direction. F = zk, S is the surface of the sphere x2 + y 2 + z 2 = 4 in the first octant, direction away from the origin. Hint: First solve for z. Since it is the first octant, you can only take positive root. Then you have the surface as z=f(x,y). You can use the trick we learned in the class. At the end, to evaluate double integral, you can convert the integral into polar coordinat O 21 OOO O

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the flux of the vector field F across the surface S in the indicated direction.
F = zk, S is the surface of the sphere x2 +y 2 + z2 = 4 in the first octant, direction away from the origin. Hint: First solve for z. Since it is the first octant, you can only take positive square
root.
Then you have the surface as z=f(x,y). You can use the trick we learned in the class. At the end, to evaluate double integral, you can convert the integral into polar coordinate.
O 3"
O 2T
Transcribed Image Text:Find the flux of the vector field F across the surface S in the indicated direction. F = zk, S is the surface of the sphere x2 +y 2 + z2 = 4 in the first octant, direction away from the origin. Hint: First solve for z. Since it is the first octant, you can only take positive square root. Then you have the surface as z=f(x,y). You can use the trick we learned in the class. At the end, to evaluate double integral, you can convert the integral into polar coordinate. O 3" O 2T
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