Find the force acting in all members of the truss shown in Figure T-01. 1m 0.75 m E 1m Figure T-01 F 1 m 50 KN 80 KN
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- find the longitudinal strtain experienced by the strut it width is 8mm and height is 20mmAn aluminum rod is hanging from one end. The rod is 1 m long and has a square cross section 20 mm by 20 mm. Find the extension of the rod resulting from its own weight. Take E = 70 GPa and the unit weight = 27 kN/m3.9-8kN stress/force on the AB rope holding the base station shown below There are. In order for the net force at point A of this base station to be downward What is the stress/force that should be on the AC rope? A) 5556 N C) 7356 N B) 8200 N D) 3648 N E) 1228 N
- Find the residual forces acting in a truss with members AC=1000N (T), EG=520N (T), and FH=1200N (C) as indicated in Figure 2. Determine the loads P1, P2, and P3 as well. Use four decimal places.The strut is supported by a pin at C and an A-36 steel guy wire AB. If the wire has a diameter of 1,2 m , determine how much it stretches when the distributed load acts on the strut.A bar made of A-36 steel has the dimensions shown below. If an axial force of P = 64 kN is applied to the bar. Use E = 200 GPa for A-36 steel. Determine the change in its length: ______ µm.
- The bar ABCD has rigid supports and consists of three prismatic solid segments, as shown. The end segments have cross-sectional area A1 = 840 mm2 and length L1 = 200 mm. The middle segment has cross-sectional area A2 =1260 mm2 and length L2= 250 mm. Loads PB and PC are equal to 25.5 kN and 17.0 kN, respectively. Determine the magnitude of the compressive axial force FBC (kN).For the same question, the Driving force (pressing force) of the Nut will be measured with the Torque wrench. While tightening the nut, the contact surface rubs against the fixed surfaces. Accordingly, how much MOMENT do we need to read from the Torque wrench in order to create a force of Fçak=1101 kgf? (Given: Screw pitch M30, Root diameter d1=25.8 mm) Outer diameter of the friction surface under the nut D42 mmFriction coefficient μ=0.6other given: T(sub B) = 80.11 T = 5.67 kN-m