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Find the general solution for the following differential equation: ty' + 2y = 5t² + 5t - 7 Then find the particular solution that satisfies the initial value y(1) = -9.3. General Solution: y(t) Particular Solution: y(t) If you don't get this in 5 tries, you can get a hint.

Find the general solution for the following differential equation: ty' + 2y = 5t² + 5t - 7 Then find the particular solution that satisfies the initial value y(1) = -9.3. General Solution: y(t) Particular Solution: y(t) If you don't get this in 5 tries, you can get a hint.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I tried first consider the complementary equation and find a solution of y1(x) before solving the rest,

I did mine and I wonder what I did was correct or not?

Find the general solution for the following differential equation: ty' + 2y = 5t² + 5t - 7 Then find the particular solution that satisfies the initial value y(1) = -9.3. General Solution: y(t) = Particular Solution: y(t) If you don't get this in 5 tries, you can get a hint. =
Transcribed Image Text:Find the general solution for the following differential equation: ty' + 2y = 5t² + 5t - 7 Then find the particular solution that satisfies the initial value y(1) = -9.3. General Solution: y(t) = Particular Solution: y(t) If you don't get this in 5 tries, you can get a hint. =
Problem S. Find the general solution for the following differential equation ty² + 2y = 5 € ² + 56-7 2 ty₁t2g = 0 29 -29 = -29 ty₁ = y tỷ t s y 2 Skj dy dv. f/2 = |dt Inly) th=-2/n(t) + C₁ cimgitek = = 2loce) + C₂ 1y₁ = C(=D(E) + (₁) 4 y = Ce=²ince) | 4 This is a correct 9₁ = @²²/acty 4 > 7 complementary equation?
Transcribed Image Text:Problem S. Find the general solution for the following differential equation ty² + 2y = 5 € ² + 56-7 2 ty₁t2g = 0 29 -29 = -29 ty₁ = y tỷ t s y 2 Skj dy dv. f/2 = |dt Inly) th=-2/n(t) + C₁ cimgitek = = 2loce) + C₂ 1y₁ = C(=D(E) + (₁) 4 y = Ce=²ince) | 4 This is a correct 9₁ = @²²/acty 4 > 7 complementary equation?
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