Find the general solution of у "— 2у "— 16у'+ 32у -0 given that r = 2 is a root of the characteristic equation. 4x -4x -4x b) O y=C, e*+Ce 4 x c) O y=C,e*+C, 4x d) O y-c, + -4x C, e 2 4x + C,e + C, f) O None of the above.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Find the general solution of
у "— 2у "— 16у'+ 32у -0
given that r = 2 is a root of the characteristic equation.
4x
-4x
-4x
b) O y=C, e*+Ce
4 x
c) O y=C,e*+C,
4x
d) O y=C, e*.
+ c,é
-4x
C, e
2
4x
+ C,e
+ C,
f) O None of the above.
Transcribed Image Text:Find the general solution of у "— 2у "— 16у'+ 32у -0 given that r = 2 is a root of the characteristic equation. 4x -4x -4x b) O y=C, e*+Ce 4 x c) O y=C,e*+C, 4x d) O y=C, e*. + c,é -4x C, e 2 4x + C,e + C, f) O None of the above.
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