can you please answer f.? Problem 8: A circular wire loop of radius r = 0.15 m and resistance R = 8.5 Q rotates about a shaft through itsdiameter at a constant rate of f = 5.35 Hz in a uniform B = 0.37-T magnetic field directed perpendicular to therotation axis. The plane of the loop is perpendicular to the magnetic field at time t = 0.Part (a) Select the correct expression for the time-dependent magnetic flux through the loop.SchematicChoice :+ = TB cos(ft)r²O = 27B cos(27 ft)r²O = TB cos(27 ft)r1B cos(2T ft)r²D = TB cos(27 f )r²= TB cos(27 ft)r²Part (b) Find the value of the magnetic flux through the loop, in webers, at time t = 0.102 s.Numeric : A numeric value is expected and not an expression.Part (c) Select the expression for the time-dependent emf induced in the loop based on the expression you entered in part(а).В.SchematicChoice :E = 2n² fr² B sin(27f) E= 2n² fr²B cos(27f)E = ar² B cos(27 ft) E = 2n² fr² B cos(2rft) E = 2n² fr²B sin(2n ft)= ar²B sin(27 ft)Part (d) Calculate the induced emf in the loop, in volts, at time t = 0.102 s.Numeric : A numeric value is expected and not an expression.Part (e) Select the expression for the induced current in the loop based on the expression you entered in part (c).SchematicChoice :4n f2r³B473 f²r³B- sin(27 ft) I =cos(27 ft) I=Rsin(27 f)I =RI = 2n² fr² B sin(27f) I= 2n² fr² B sin(2rft)27² fr²BI2E )sin(27 ft)RPart (f) Find the induced current in the loop, in amperes, at time t = 0.102 s.Numeric : A numeric value is expected and not an expression.I =

Induced current is induced emf devided by Resistance , whereas induced emf is given by rate of…

Answered: Find the induced current in the loop,…

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Find the induced current in the loop, in amperes, at time t = 0.102 s.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 28P

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Question

can you please answer f.?

Problem 8: A circular wire loop of radius r = 0.15 m and resistance R = 8.5 Q rotates about a shaft through its
diameter at a constant rate of f = 5.35 Hz in a uniform B = 0.37-T magnetic field directed perpendicular to the
rotation axis. The plane of the loop is perpendicular to the magnetic field at time t = 0.
Part (a) Select the correct expression for the time-dependent magnetic flux through the loop.
SchematicChoice :
+ = TB cos(ft)r²
O = 27B cos(27 ft)r²
O = TB cos(27 ft)r
1
B cos(2T ft)r²
D = TB cos(27 f )r²
= TB cos(27 ft)r²
Part (b) Find the value of the magnetic flux through the loop, in webers, at time t = 0.102 s.
Numeric : A numeric value is expected and not an expression.
Part (c) Select the expression for the time-dependent emf induced in the loop based on the expression you entered in part
(а).В.
SchematicChoice :
E = 2n² fr² B sin(27f) E= 2n² fr²B cos(27f)
E = ar² B cos(27 ft) E = 2n² fr² B cos(2rft) E = 2n² fr²B sin(2n ft)
= ar²B sin(27 ft)
Part (d) Calculate the induced emf in the loop, in volts, at time t = 0.102 s.
Numeric : A numeric value is expected and not an expression.
Part (e) Select the expression for the induced current in the loop based on the expression you entered in part (c).
SchematicChoice :
4n f2r³B
473 f²r³B
- sin(27 ft) I =
cos(27 ft) I=
R
sin(27 f)
I =
R
I = 2n² fr² B sin(27f) I= 2n² fr² B sin(2rft)
27² fr²B
I
2E )
sin(27 ft)
R
Part (f) Find the induced current in the loop, in amperes, at time t = 0.102 s.
Numeric : A numeric value is expected and not an expression.
I =

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