Find the instantaneous velocity of the particle described in the figure below at the x(m) 10 8- 6 4 (s) 1 4 6 -2 -4 t = 1.3 s m/s (a) t = 3.1 s m/s (b) t = 4.8 s m/s (c) (d) t = 7.1 s m/s
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Given is position vs time Graph
Instantaneous velocity (v)= slope of position vs time graph at that instant
= dx/dt
(a) t= 1.3 s
v = dx/dt
=10/2 = 5 m/s
Slope is same for t=0 to t= 2 s
(b) t = 3.1 s
v = dx /dt = ∆x/∆t
= (5-10)/(4-2)
= -5/2 = - 2.5m/s
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