Find the limit by rewriting the fraction first. ху — 2у - 6х + 12 lim х - 2 (ху) -> (2,1) x+2 ху - 2у - 6х + 12 lim (Simplify your answer.) %3D х -2 (х,у) ->(2,1) x+2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 58E
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Find the limit by rewriting the fraction first.
ху — 2у — 6х + 12
lim
х - 2
(х,у) —(2,1)
x#2
ху - 2у - 6x + 12
х -2
lim
(Simplify your answer.)
%3D
(х,у)->(2,1)
x+2
Transcribed Image Text:Find the limit by rewriting the fraction first. ху — 2у — 6х + 12 lim х - 2 (х,у) —(2,1) x#2 ху - 2у - 6x + 12 х -2 lim (Simplify your answer.) %3D (х,у)->(2,1) x+2
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