Find the limit L (if it exists). If it does not exist, explain why. (If an answer does not exist, enter DNE.) t3 + 1, t < 1 lim h(t) t→1 -(t + 1), t> 1 L = The limit does not exist at x = 1 because the function does not approach f(1) as x approaches 1. The limit does not exist at x = 1 because the function approaches different values from the left and right side of 1. The limit does not exist at x = 1 because the function value is undefined at x = 1. The limit does not exist at x = 1 because the function is not continuous at any x value. The limit exists at x = 1.

College Algebra (MindTap Course List)
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Author:R. David Gustafson, Jeff Hughes
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Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
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Find the limit L (if it exists). If it does not exist, explain why. (If an answer does not exist, enter DNE.)
t3 + 1,
t < 1
lim h(t)
t→1
-(t + 1), t> 1
L =
The limit does not exist at x = 1 because the function does not approach f(1) as x approaches 1.
The limit does not exist at x = 1 because the function approaches different values from the left and right side of 1.
The limit does not exist at x = 1 because the function value is undefined at x = 1.
The limit does not exist at x = 1 because the function is not continuous at any x value.
The limit exists at x = 1.
Transcribed Image Text:Find the limit L (if it exists). If it does not exist, explain why. (If an answer does not exist, enter DNE.) t3 + 1, t < 1 lim h(t) t→1 -(t + 1), t> 1 L = The limit does not exist at x = 1 because the function does not approach f(1) as x approaches 1. The limit does not exist at x = 1 because the function approaches different values from the left and right side of 1. The limit does not exist at x = 1 because the function value is undefined at x = 1. The limit does not exist at x = 1 because the function is not continuous at any x value. The limit exists at x = 1.
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