Find the load of the system of convergent forces acting on the body AL in 400N the figure (3) k2m.
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- A lifeboat hangs from two ship's davits. as shown in the figure. A pin of diameter d = 0.80 in. passes through each davit and supports two pulleys. are on each side of the davit. Cables attached to the lifeboat pass over the pulleys and wind around winches that raise and lower the lifeboat. The lower parts of the cables are vertical and the upper parts make an angle a =15° with the horizontal. The allowable tensile force in each cable is 1800 lb, and the allowable shear stress in the pins is 4000 psi. If the lifeboat weighs 1500 lb, what is the maximum weight that can be carried in the lifeboat?Repeat Problem 11.2-14 using L = 12 ft, ß = 0.25 kips/in., ßRl= 1.5ßL2, and ßR2= 2 ßR1.9-8kN stress/force on the AB rope holding the base station shown below There are. In order for the net force at point A of this base station to be downward What is the stress/force that should be on the AC rope? A) 5556 N C) 7356 N B) 8200 N D) 3648 N E) 1228 N
- The truss above has concentrated loads as shown. The wind loads of 50 KN are perpendicular to the member AF. Solve for the forces acting on the members BE, DE, DG, FG by the method of joints. Show all solutions please don't skip. Please show to did u get FBC, FBE, FBD Thanks!FBDsin30-FBEsin60-FBC = 243.301KN then FBC = -625.77KN. how? please teach me how thanks!Engineering Mechanics (Like/Thumbs-up will be given. Write the solutions&FBD legibly. Include negative sign if in Compression, ex. -1,500 or if in Tension, ex. 1,500. Round to the nearest whole number.) I. (Multiple Choice) From the given A-Frame shown above, which statements are true: a. The horizontal reaction at C is equal to 0 b. The vertical reaction at A is upward c. The horizontal reaction at pins B and D are equal in magnitude d. Member BD is a two-force member e. None of the above II. (Compute for the external reactions for all members of the frame shown): > Vertical Reaction at A > Horizontal Reaction at A > Vertical Reaction at E > Vertical Reaction at D > Vertical Reaction at B > Vertical Reaction at C > Horizontal Reaction at C > Horizontal Reaction at B > Horizontal Reaction at DTwo plates of which (2.5 d) and d as outer and inner diameter respectively and thickness 25 mm each are held together by means of a bolt. The bolt material S-400 N/mm² and E210000 N/mm² while plate material E= 72000 N/mm². The initial preload in the bold is 6.0 KN and force on the joint is 12 kN. Find out size of bolt assuming factor of safety 2.0.
- 1- The problem sketch shows___loads. 2- The problem solution provides___free body diagrams(FBDs).Shear strength value τ = 200 MPaThe plate connection made with bolts is given in the figure. P = 70kNrequired for the safe transfer of the load of valueDetermine the minimum bolt diameter.A load of F = 14kN is applied to a circular chain link in the figure. Since σem = 600 N / mm2What is the diameter of the chain link in order to safely carry the given load?
- load of 12 kN is raised by means of a screw jack. The mean diameter of the square threaded screw is 48 mm and the pitch is 12 mm. A force of 180 N is applied at the end of a lever to raise the load. Determine the length of the lever to be used and the mechanical advantage obtained. the screw self-locking? Take µ = 0.12.Static Problem. Indications:The system shown is composed of an ABG bar, supported by a pin at point A and by a collarsmooth at point B (the collar slides on the bar ABG). The collar is pinned to the BDE bar, and theRod BDE is supported by a pin at D and a cable at end E.Based on the above, determine:a) The load P, such that the cable force EF is T.b) The internal loads in a section passing through point G (normal and shear force, and momentflexing).c) Draw bar BDE horizontally and generate the shear force and moment diagramsflexing Indicate the maximum values of shear force and bending moment and their location.?= 22 lb ? = 7 in ? = 6 inow step by step solution with free body diagram