Find the minimum and maximum values of the function on the given interval by comparing values at the critical points and endpoints. f(x) = 5 tan¹ (x) - x. [1.9] (Express numbers in exact form. Use symbolic notation and fractions where needed.) minimum: 3.5357436 Incorrect aximum: incorrect -2

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Your answer is wrong They said write anwer in exact form so plz give me answer in exact form not in points Are u really mad I am not mad that posting again and again Plz give me exactly soloution
Find the minimum and maximum values of the function on the given interval by comparing values at the critical points
and endpoints.
f(x) = 5 tan¹ (x) - x. [1,9]
(Express numbers in exact form. Use symbolic notation and fractions where needed.)
minimum: 3.5357436
Incorrect
maximum:
incorrect
Transcribed Image Text:Find the minimum and maximum values of the function on the given interval by comparing values at the critical points and endpoints. f(x) = 5 tan¹ (x) - x. [1,9] (Express numbers in exact form. Use symbolic notation and fractions where needed.) minimum: 3.5357436 Incorrect maximum: incorrect
F
f(1)
check valve
x = 2 -2 are
2
=
‡ (9)
x² = 4
=
=
#2
(2) = 5 tam ¹2 -2
5 tom²¹1 - 1
of function
5 tam
(2) = 5 ton (2) +2
Maximum value
Minimum value
9-9
critical point
= 0.78539816 X5 -1
= 2.9269908
= 5x1.10714872 -2
= 3.5357436
fi
at critical points and
end boints.
- 5X -|.10714872 t2
= -3.535746
= 5x1.46013911-9
=-1.69930445
3.5357436
-3.535 74 36
2
at se=2
at se=-2
Was this solution
helpful?
√x 8
Transcribed Image Text:F f(1) check valve x = 2 -2 are 2 = ‡ (9) x² = 4 = = #2 (2) = 5 tam ¹2 -2 5 tom²¹1 - 1 of function 5 tam (2) = 5 ton (2) +2 Maximum value Minimum value 9-9 critical point = 0.78539816 X5 -1 = 2.9269908 = 5x1.10714872 -2 = 3.5357436 fi at critical points and end boints. - 5X -|.10714872 t2 = -3.535746 = 5x1.46013911-9 =-1.69930445 3.5357436 -3.535 74 36 2 at se=2 at se=-2 Was this solution helpful? √x 8
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