Hi! Can you help me with these? Assignment: Find the percentage of each problem. Balance it if necessarry. Show your solution. (kindly refer to the picture on how must the solution look like) 2. 2Fe + 2CuSO8 -----> 2Cu + 2FeSO8 DRILLS: (ANSWERS )PART 2:Computing for the % of elements:% 2Hgmass of Hg x 100mass of 2HgO402 anqu466 anuх 1000.862710086.27 %% 0,mass of O, x 100mass of 2HgO64 amu466 amuX 1000.137310013.73 %%3|XASUS4S LDDER- lock Remaining Meeting Time: 02:39Equation:NaClNaClFormula:NAt. wtNno. of atomsNa =Naat, wt X Nano. of atoms23 amu x 1:23 атиCI = Cl,Clat, wt X CIno. of atoms35 amu x I= 35 amuAt. wtNa+ClNaCl(23 amu)(35 amu)(58 amu)02

Given: Balanced equation: 2. 2Fe + 2CuSO8 → 2Cu + 2FeSO8

Answered: : Find the percentage of each problem.…

: Find the percentage of each problem. Balance it if necessarry. Show your solution. (kindly refer to the picture on how must the solution look like) 2. 2Fe + 2CuSO8 -----> 2Cu + 2FeSO8

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter9: Gases

Section: Chapter Questions

Problem 86E: During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6...

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Question

Hi! Can you help me with these?

Assignment: Find the percentage of each problem. Balance it if necessarry. Show your solution. (kindly refer to the picture on how must the solution look like)

2. 2Fe + 2CuSO8 -----> 2Cu + 2FeSO8

DRILLS: (ANSWERS )
PART 2:
Computing for the % of elements:
% 2Hg
mass of Hg x 100
mass of 2HgO
402 anqu
466 anu
х 100
0.8627
100
86.27 %
% 0,
mass of O, x 100
mass of 2HgO
64 amu
466 amu
X 100
0.1373
100
13.73 %
%3|
X
ASUS
4S LDD
E
R
- lock

Remaining Meeting Time: 02:39
Equation:
Na
Cl
NaCl
Formula:
NAt. wt
Nno. of atoms
Na =
Naat, wt X Nano. of atoms
23 amu x 1:
23 ати
CI = Cl,
Clat, wt X CIno. of atoms
35 amu x I
= 35 amu
At. wt
Na
+
Cl
NaCl
(23 amu)
(35 amu)
(58 amu)
02

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