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Q: 120°
A: Given: The magnitude of the forces are F1=75 N and F2=60 N. The angle between forces is 120o.
Find the resultant of the following forces by component method: F1 =12N,south; F2 =24N, 30° north of west; F3 = 15N, 75° south of west; and F4 = 32 N, 50° south of east.
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- In a tug-of-war game on one campus, 15 students pull on a rope at both ends in an effort to displace the central knot to one side or the other. Two students pull with force 196 N each to the light, four students pull with force 98 N each to the left, five students pull with force 62 N each to the left, three students pull with force 150 N each to the right, and one student pulls with force 250 N to the left. Assuming the positive direction to the tight, express the net pull on the knot in terms of the unit vector. How big is the net pull on the knot? In what direction?find the resultant of the following forces by component method: f1= 12 n, south; f2=24n, 30 degrees north of west; f3=15n, 75 degrees south of west; anf f4= 32 n, 50 degrees south of east.Two forces act perpendicular to each other with 100 N in the +x and 150 N in the +y. Which of the following is the magnitude direction of the resultant force?
- In a forest, an explorer walks 13 km due east, then 18 km north, then he rested for an hour. After resting, the explorer continued walking 3 km north and then finally reached the hidden cabin at 72 m west. What is the total distance walked? What is the resulting displacement of the explorer from the starting point? Using the component method, find the complete resultant of the following forces: F= 2m, 40° N of E, and G = 4m at 127° counterclockwise from East?Determine the resultant of the given forces. f1 acting due west with a magnitude of 15 N and f2 acting due south with a magnitude of 20 NFind the resultant of the following forces by polygon method : F1=12 N, South; F2= 24N 30 degree north of west; F3= 15 N, 75 degree of west; and F4=32 N, 50 degree south of east
- A vector force of magnitude 100N moves in the North East direction, making an angle of 40° with the horizontal. Compute the vertical and horizontal components of the force.The following forces acts on an object: 10N north, 20N southeast, and 5N to the west. Thr magnitude of the resultant is?At what angle 8 must the 800-lb force be applied in order that the resultant R of the two forces has a magnitude of 20( lb? For this condition, determine the angle B between R and the vertical.
- find the angle between two vector forces whose magnitude are F and 3F and the magnitude of whose resultant is 3F1660N 24 Degrees East of North. 1154N East. 961N South. 0N West. The Information above shows the forces acting on a 845 kg object. What is the acceleration vector that results from these forces? 4.82 m/s2, 23.3° north of east 13.8 m/s2, 16.5° south of west 6.11 m/s2, 11.2° east of north 2.26 m/s2, 16.6° north of eastvector magnitude (dynes,g.cm/s^2) direction f1 142,100 20 degree f2 102,900 105 degree f3 53,900 197 degree equilibrant (force table) 142,590 249 degree resultant (force table) 142,590 69 degree north of east resultant (Graphical method) resultant (component Method % error (force table vs component method) % error (graphical method vs component method)
