Find the Solution (2x+3)y' =y+ (2x+ 3) 1/2; when x = - 1, y =0 2y = (2x+ 3) 1/2 In (2r + 3) 2x = (2y + 3) 1/2 in (2y + 3) 2y = (x+3) 1/2 In (x+3) 2x = (y+3) 1/2 In (y + 3)

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