Find the solution of the given initial value problem: y" + y' = sec(t), y(0) = 6, y′(0) = 7, y″(0) = −3. y(t): = 5 + 6 cos(t) +5 sin(t) + ln(sec(t) + tan(t)) — t cos(t) + sin(t) ln(cos(t)) - X

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