Find the standard cell potential for an electrochemicalcell with the following cell reaction and write its cell notation. 3+ 2+ 2+ Fe (aq)+ Cu(s) → Cu (aq)+ Fe (aq) Given the following reduction potentials: 3+ Fe (aq) + e → 38 (aq) E°= 0.77 v 39 (aq)+2e –→ Cu (s). E°=0.34 v Solution: 3+ 40 Reduction: 2Fe (aq)+2e → (aq) E°= 0.77 V 41 42 Oxidation: Cu(s) → (aq)+2e E° = 43 2+ 44 45 Overall Reaction: Cu+ → Cu + E°= CellNotation: Oxidation Anode || ReductionCathode +2 +3 Cu(s) | Cu (aq) || Fe* (aq) | Fe (aq)

Find the standard cell potential for an electrochemicalcell with the following cell reaction and write its cell notation. 3+ 2+ 2+ Fe (aq)+ Cu(s) → Cu (aq)+ Fe (aq) Given the following reduction potentials: 3+ Fe (aq) + e → 38 (aq) E°= 0.77 v 39 (aq)+2e –→ Cu (s). E°=0.34 v Solution: 3+ 40 Reduction: 2Fe (aq)+2e → (aq) E°= 0.77 V 41 42 Oxidation: Cu(s) → (aq)+2e E° = 43 2+ 44 45 Overall Reaction: Cu+ → Cu + E°= CellNotation: Oxidation Anode || ReductionCathode +2 +3 Cu(s) | Cu (aq) || Fe* (aq) | Fe (aq)

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter13: Chemical Reactions

Section: Chapter Questions

Problem 34SA

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