Fire fighter had an accident leads to injury in his thigh, caused fracture in his femur (consider it has cylindrical shape). Due to this injury, the shorting in this bone (change in the length failure) is 0.08 mm. Calculate the length of the bone after injury with taking into consideration that the applied force was 500 N, and the radius of his bone is 2 cm with the cross section equal to 0.00125 m2, (Young's modulus = 1.5 X 109 N/m2) Note : answer the question on the side paper and choose the result from the form as number only with its units
Fire fighter had an accident leads to injury in his thigh, caused fracture in his femur (consider it has cylindrical shape). Due to this injury, the shorting in this bone (change in the length failure) is 0.08 mm. Calculate the length of the bone after injury with taking into consideration that the applied force was 500 N, and the radius of his bone is 2 cm with the cross section equal to 0.00125 m2, (Young's modulus = 1.5 X 109 N/m2) Note : answer the question on the side paper and choose the result from the form as number only with its units
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter12: Static Equilibrium And Elasticity
Section: Chapter Questions
Problem 56P: Alarge uniform cylindrical steel rod of density =7.8g/cm3 is 2.0 m long and has a diameter of 5.0...
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Fire fighter had an accident leads to injury in his thigh, caused fracture in his femur (consider it has cylindrical shape). Due to this injury, the shorting in this bone (change in the length failure) is 0.08 mm. Calculate the length of the bone after injury with taking into consideration that the applied force was 500 N, and the radius of his bone is 2 cm with the cross section equal to 0.00125 m2, (Young's modulus = 1.5 X 109 N/m2) Note : answer the question on the side paper and choose the result from the form as number only with its units
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