First Derivative Test is not exhaustive Sketch the graph of a(simple) nonconstant function f that has a local maximum atx = 1, with f′(1) = 0, where f′ does not change sign frompositive to negative as x increases through 1. Why can’t the FirstDerivative Test be used to classify the critical point at x = 1 as alocal maximum? How could the test be rephrased to account forsuch a critical point?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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First Derivative Test is not exhaustive Sketch the graph of a
(simple) nonconstant function f that has a local maximum at
x = 1, with f′(1) = 0, where f′ does not change sign from
positive to negative as x increases through 1. Why can’t the First
Derivative Test be used to classify the critical point at x = 1 as a
local maximum? How could the test be rephrased to account for
such a critical point?

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