First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) mA Similarly the current across R2 is: 12 = mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the currents across each resistor: 1=1+/2+13 | = mA Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Reg =1/R1+1/R2 +1/ Thus, Reg Ω

First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) mA Similarly the current across R2 is: 12 = mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the currents across each resistor: 1=1+/2+13 | = mA Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Reg =1/R1+1/R2 +1/ Thus, Reg Ω

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter10: Direct-current Circuits

Section: Chapter Questions

Problem 37P: Consider the circuits shown below, (a) What is the current through each resistor in part (a)? (b)...

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