following differential equations has a point near x = 1 as an irregular singular =y" - 2 (x² + 4x - 5) y' + 8 xy = 0 y" - 2x (x + 4) y' + 8(x - 1) y = 0 =-3)² y" - 2(x-4) y' + 8 xy = 0 c − 3) y″ − 2(x + 3)³ (x − 4) y = 0

Q: Find the Inverse Laplace Transform of 1 s²-8s+25

A: The given function is 1s2-8s+25 completing squares 1s2-8s+25=1s2-8s+16+9=1s2-24s+42+9=1s-42+9

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A: option c is correct i.e. (c) -1.92711

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A: We can solve this using given information and relative error

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A: We can solve this using given information and relative error

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Q: Consider y' - 2y = 3e²x with y(0) = 2. Using Runge-Kutta method with h=0.1, find the relative error…

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