For #1 to #7; Given: Parallelogram CONE; Prove: CO NE, ON EC Choices for #1 to #7 a) СРСТС b) "CO = NE, ON = EC c) By construction d) Reflexive property e) Parallelogram property 2 f) SSS triangle congruence postulate g) SAA triangle congruence postulate h) Alternate Interior Angles are Congruent i) Parallelogram property 1 Statements Reasons 1. Given ZC ZN Draw OE ZCEO ZNOE OE = OE ΔCEO ΔΝΟΕ CO NE, ON = EC 234567

Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter6: Circles
Section6.3: Line And Segment Relationships In The Circle
Problem 38E: The center of a circle of radius 3 inches is at a distance of 20 inches from the center of a circle...
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For #1 to #7; Given: Parallelogram CONE; Prove: CO = NE, ON EC
C
Choices for #1 to #7
a) СРСТС
b)"CO = NE, ON = EC
c) By construction
d) Reflexive property
e) Parallelogram property 2
f) SSS triangle congruence postulate
g) SAA triangle congruence postulate
h) Alternate Interior Angles are Congruent
i) Parallelogram property 1
N
Statements
Reasons
1.
Given
2.
Draw OE
3.
ZCEO EZNOE
4.
OE OE
5.
ΔCEO ΔΝΟΕ
6.
CO NE, ON= EC
7.
Transcribed Image Text:on the blank. For #1 to #7; Given: Parallelogram CONE; Prove: CO = NE, ON EC C Choices for #1 to #7 a) СРСТС b)"CO = NE, ON = EC c) By construction d) Reflexive property e) Parallelogram property 2 f) SSS triangle congruence postulate g) SAA triangle congruence postulate h) Alternate Interior Angles are Congruent i) Parallelogram property 1 N Statements Reasons 1. Given 2. Draw OE 3. ZCEO EZNOE 4. OE OE 5. ΔCEO ΔΝΟΕ 6. CO NE, ON= EC 7.
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