b)For a 3 phase 400V power supply, given the prospective fault current at point A are, i). 3Øsymmetrical fault is 11.6 kA, ii). line-to-line fault is 10 kA. Given cable length is 160 meterand Z cable = 0.0055 + j0.0036 per phase per 20 meter.ВA30 supply400 (V)H to loadnon armoured cable 4 x 1C 120mm2 x LPEINVESTIGATE the prospective fault current before the load fori).3 phase symmetrical fault.ii).Line-to-line fault.

at point A 3 phase symmetrical fault =11.6 A line to line fault current =10 kA V=400 V per phase…

For a 3 phase 400V power supply, given the prospective fault current at point A are, i). 3Ø symmetrical fault is 11.6 kA, ii). line-to-line fault is 10 kA. Given cable length is 160 meter and Z cable = 0.0055 + j0.0036 per phase per 20 meter. A B 30 supply 400 (V) H to load non armoured cable 4 x 1C 120mm? × LPE INVESTIGATE the prospective fault current before the load for i). 3 phase symmetrical fault. ii). Line-to-line fault.

For a 3 phase 400V power supply, given the prospective fault current at point A are, i). 3Ø symmetrical fault is 11.6 kA, ii). line-to-line fault is 10 kA. Given cable length is 160 meter and Z cable = 0.0055 + j0.0036 per phase per 20 meter. A B 30 supply 400 (V) H to load non armoured cable 4 x 1C 120mm? × LPE INVESTIGATE the prospective fault current before the load for i). 3 phase symmetrical fault. ii). Line-to-line fault.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.60P: PowerWorid Simulator case Problem 3_60 duplicates Example 3.13 except that a resistance term of 0.06...

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