For a dilute gas of N monatomic particles with mass m and total energy E, use the Sackur- Tetrode equation for the entropy S V 5 = log + NkB NX3 2 th to derive expressions for the pressure and internal energy in terms of the temperature T and volume V. [You may use that X2 = 3πh² N/(mE).] th
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Answer in 90 minutes please.
![For a dilute gas of N monatomic particles with mass m and total energy E, use the Sackur-
Tetrode equation for the entropy
S
V
5
= log
+
NkB
NX3
2
th
to derive expressions for the pressure and internal energy in terms of the temperature T and
volume V.
[You may use that X2 = 3πh² N/(mE).]
th](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb360a251-a88e-4e24-b6e1-ceeebc35a45e%2F7bb6b8e9-3ca6-4690-8714-a13363404695%2F4lo2ch_processed.jpeg&w=3840&q=75)
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- A dilute gas expands quasi-statically to three times its initial volume. Is the final gas pressure greater for an isothermal or an adiabatic expansion? Does your answer depend on whether the gas is monatomic, diatomic, or polyatomic?Write the mathematical relationships for each of the following Conclude the thermodynamic properties (parameters) of ideal gas same as ( energy , prussure, entropy , specific heat at fixed prussure , specific heat at fixed volume ) e 12:31 VProblem 1: In statistical mechanics, the internal energy of an ideal gas is given by: N. aNkB 2/3 (3NKB U = U(S,V) = е where a is a constant. 1- Show that the variation of the internal energy is given by: 2 dS - \3V 2 dU = dV \3NkB 2- Using the fundamental relation of thermodynamic dU = T.ds – p. dV, show that the equation of state PV = nRT follows from the first expression of U.
- For one component gas that is confined in a box with volume V. We can get the entropy of the gas as S= Nk, in- where N is the total a² number of atoms, a is the radius of the atom. Can you guess how it is obtained?a. Find an appropriate expression for the change in entropy in the following two cases: 1) S=S(T, V) 2) s= S(T, P) Where: S is entropy, T is temperature, V is volume, P is pressure b. Prove the following two themodynamie property relationships (똥),-() 8C, Where: T, P. V are temperature, pressure and volume, respectively. C, and C, are specific heats at constant volume and constant pressure, respectively.Problem #2 For heat exchange between a thermal reservoir at 300 K and a constant volume system containing one mole of monatomic ideal gas: a) Derive the equation for the total change in entropy for a designed initial system temperature Tj. b) Plot AStotal vs. Tsys for the initial system temperature ranging from 160 K to 500 K in increments of 10 K (i.e., Tsys = 160 K, 170 K, ... , 500 K). Use Matlab, Excel or similar plotting software for your plot. Label the plot axes and include units. %D
- En: The latent heat of vaporization of water at 100 °C is 40.6 kJ mol-1and when 1 mol of water is vaporized at 100 °C and 1 atm pressure, the volume increase is 30.19 dm3. Calculate the work done by the system, the change in internal energy AU, the change in Gibbs' energy AG and the entropy change AS.-Consider a lassi cal ideal gas Consisting of N atoms of mass M in thermal bniem at anprete T, miving in a equile 3 dimensional 4bnum harmonic potenhal Well. mutr? 2 2. v(r)s a. Cal culate The par n'tion funchm of The system. b.Compute the average energy of the Sy stem C. Comprute The entropy of the system,dU =T dS – P dV Re-arrange the thermodynamic identity by solving for dS. Assume we are applying this new expression to an ideal gas, re-write the du term in terms of the appropriate heat capacity and temperature. Re-write the coefficient of the dV term in terms of volume. Connect these “classical" expressions for entropy to the "modern" interpretation where we are concerned with the uncertainty associated with position and momentum of the particles in an ideal gas. Answer with sentences. Now, re-write the expression in terms of enthalpy so you can connect entropy with enthalpy. Expalin why this final expression makes sense.
- Problem 3: Consider an Einstein solid with N oscillators and total energy U = qe, in the limit N,q » 1 (with no assumptions made about the relative size of N and q). + N° (9 +N\9 a) Starting with this formula, find an expression for the entropy of an Einstein solid as a function of N and q. Explain why factors omitted from the formula have no effect on the entropy. b) Derive an expression for the temperature of the solid, as a function of N and q. Simplify your expression as a much as possible. c) Invert the result of part (c) to get the energy U as a function of temperature T. As always, simplify the final result as much as possible. d) Show that, in the high temperature limit (q » N), the heat capacity is C = Nkg. (Hint: when x is small, e* = 1+ x.) Is this the result you would expect? Explain. e) Plot energy U vs. temperature T using dimensionless variables, Cy/(Nkg) vs. t = kgT/e, for t in the range from 0 to 2. Discuss your prediction for the heat capacity at low temperature…Entropy (s) is aun extensive variable . & S(U,V,N) Uo Internal Energy V→ Volume Number of particles find an Euler equation For entropeConsider a van der hoal's gas tuat undergoes an 1sothermai expansion focm Volume V, to Volume Uz 9 Caiculate the Change in the Helmholte free energy b) trom the theory GF thermodynamics, with I and V Independent, = T3)-p. Shaw that the Change In Internal energyis AUEa )
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