For a single, isolated point charge carrying a charge of q= 57.7 pC, one equipotential surface consists of a sphere of radius r₁= 18.9 mm centered on the point charge as shown. What is the potential on this surface? potential: To draw an additional equipotential surface separated by 16.8 V from the previous surface, how far from the point charge should this second surface be? This surface must also meet the condition of being farther from the point charge than the original equipotential surface is. distance from point charge: mm 2

For a single, isolated point charge carrying a charge of q= 57.7 pC, one equipotential surface consists of a sphere of radius r₁= 18.9 mm centered on the point charge as shown. What is the potential on this surface? potential: To draw an additional equipotential surface separated by 16.8 V from the previous surface, how far from the point charge should this second surface be? This surface must also meet the condition of being farther from the point charge than the original equipotential surface is. distance from point charge: mm 2

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter7: Electric Potential

Section: Chapter Questions

Problem 59P: A very large sheet of insulating material has had an excess of electrons placed on it to a surface...

See similar textbooks

Similar questions

A small spherical pith ball of radius 0.50 cm is painted with a silver paint and then -10 C of charge is placed on it. The charged pith ball is put at the center of a gold spherical shell of inner radius 2.0 cm and outer radius 2.2 cm. (a) Find the electric potential of the gold shell with respect to zero potential at infinity, (b) How much charge should you put on the gold shell if you want to make its potential 100 V?
The labeled points in Figure 20.4 are on a series of equipotential surfaces associated with an electric field. Rank (from greatest to least) the work done by the electric field on a positively charged particle that moves from to , from to , from to , and from to . Figure 20.4 (Quick Quiz 20.2) Four equipotential surfaces.
Two large charged plates of charge density 30C/m2 face each other at a separation of 5.0 mm. (a) Find the electric potential everywhere, (b) An electron is released from rest at the negative plate; with what speed will it strike the positive plate?
For the arrangement described in Problem 26, calculate the electric potential at point B, which lies on the perpendicular bisector of the rod a distance b above the x axis. Figure P20.26
An electron moving parallel to the x axis has an initial speed of 3.70 106 m/s at the origin. Its speed is reduced to 1.40 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. (b) Which point is at the higher potential?
A filament running along the x axis from the origin to x = 80.0 cm carries electric charge with uniform density. At the point P with coordinates (x = 80.0 cm, y = 80.0 cm), this filament creates electric potential 100 V. Now we add another filament along the y axis, running from the origin to y = 80.0 cm, carrying the same amount of charge with the same uniform density. At the same point P, is the electric potential created by the pair of filaments (a) greater than 200 V, (b) 200 V, (c) 100 V, (d) between 0 and 200 V, or (e) 0?
The electric potential inside a charged spherical conductor of radius R is given by V = keQ/R, and the potential outside is given by V = keQ/R, Using Er = dV/dr, derive the electric field (a) inside and (b) outside this charge distribution.
The three charged particles in Figure P20.11 are at the vertices of an isosceles triangle (where d = 2.00 cm). Taking q = 7.00 C, calculate the electric potential at point A, the midpoint of the base. Figure P20.11
For the arrangement described in Problem 25, calculate the electric potential at point B, which lies on the perpendicular bisector of the rod a distance b above the x axis.
A CD disk of radius (R = 3.0 cm) is sprayed with a charged paint so that the charge varies continually with radial distance r from the center in the following manner =(6.0C/m)r/R ?. Find the potential at a point 4 cm above the center.
The three charged particles in Figure P25.22 are at the vertices of an isosceles triangle (where d = 2.00 cm). Taking q = 7.00 C, calculate the electric potential at point A, the midpoint of the base.
A very large sheet of insulating material has had an excess of electrons placed on it to a surface charge density of 3.00nC/m2 . (a) As the distance from the sheet increases, does the potential increase or decrease? Can you explain why without any calculations? Does the location of your reference point matter? (b) What is the shape of the equipotential surfaces? (c) What is the spacing between surfaces that differ by 1.00 V?