For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() {const int SIZE_LIST = 4;vector<int> keysList(SIZE_LIST);vector<int> itemsList(SIZE_LIST);unsigned int i; for (i = 0; i < keysList.size(); ++i) {cin >> keysList.at(i);} for (i = 0; i < itemsList.size(); ++i) {cin >> itemsList.at(i);} /* Your solution goes here */ cout << endl; return 0;} Please help me with this problem using c++.
For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30
Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed.
#include <iostream>
#include <vector>
using namespace std;
int main() {
const int SIZE_LIST = 4;
vector<int> keysList(SIZE_LIST);
vector<int> itemsList(SIZE_LIST);
unsigned int i;
for (i = 0; i < keysList.size(); ++i) {
cin >> keysList.at(i);
}
for (i = 0; i < itemsList.size(); ++i) {
cin >> itemsList.at(i);
}
/* Your solution goes here */
cout << endl;
return 0;
}
Please help me with this problem using c++.
Expert Answer
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