For class AB amplifier the R.M.S. input voltage is IIV and the supply voltage is ±20V and the load resistance (802) assume B=100 and VBE=0.8V, find the current through the diode, the power dissipated in the load, the power drawn by the supply, the dissipated power at each transistor, and the conversion efficiency? Hint: Po ac= η = VLp² 2RL R= Po ac Pi dc _vcc-VQ1 Ißp Pi dc = ² x TL VLP RL ILP= VPL RL IDQ= ·X VCC Vcc-(VBE1+VBE2)-VEE R+R P2Q= Pi dc - Po ac VQ1=VLP+VBE PQ=P2Q Bp=1LP

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For class AB amplifier the R.M.S. input voltage is IIV and the supply voltage is ±20V and the load
resistance (802) assume B=100 and VBE=0.8V, find the current through the diode, the power
dissipated in the load, the power drawn by the supply, the dissipated power at each transistor,
and the conversion efficiency?
Hint:
Po ac=
η =
VLp²
2RL
R=
Po ac
Pi dc
vcc-VQ1
Ißp
Pi dc =
VLP
RL
ILP=
TL
IDQ=
VPL
RL
X vcc
Vcc-(VBE1+VBE2)-VEE
R+R
P2Q= Pi dc Po ac
VQ1=VLP+VBE
PQ=P2Q
ILP
Transcribed Image Text:For class AB amplifier the R.M.S. input voltage is IIV and the supply voltage is ±20V and the load resistance (802) assume B=100 and VBE=0.8V, find the current through the diode, the power dissipated in the load, the power drawn by the supply, the dissipated power at each transistor, and the conversion efficiency? Hint: Po ac= η = VLp² 2RL R= Po ac Pi dc vcc-VQ1 Ißp Pi dc = VLP RL ILP= TL IDQ= VPL RL X vcc Vcc-(VBE1+VBE2)-VEE R+R P2Q= Pi dc Po ac VQ1=VLP+VBE PQ=P2Q ILP
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