Answered: For cross 2: Total (N) = 583 n= 4… | bartleby

Algebra & Trigonometry with Analytic Geometry

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.6: The Inverse Trigonometric Functions

Problem 91E

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Question

Give a brief analysis of the following cross 2?

For cross 2:
Total (N) = 583
n= 4
Expected (E) frequency = Total/n = 583/4= 145.75
%3D
%3D
Observed (0)
Expected (E)
(0-E)^2/E
Phenotypes
Red Eyes /Normal wings
White eyes /Normal wings
Red eyes/vertical wings
White eyes/Vertical wings
Total (N)
(0-E)^2
248
145.75
10455.0625
71.7328
234
145.75
7788.0625
53.4344
57
145.75
7876.5625
54.0416
44
145.75
10353.0625
71.0330
583
Chi-square test statistic () =
250.2419
%3D
Chi-square test statistic (x³) = 250.2419
%3D

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