Question
Asked Dec 23, 2019
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For Exercise, find an equation of the form  y = ax2 + bx + c that defines the parabola through the three noncollinear points given.

(0, −4), (2, −6), (−3, −31)

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Expert Answer

Step 1

Consider the given equation of parabola:

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y = ax + bx +c

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Step 2

Now, parabola passes through the point (0, - 4), so it will satisfy the equation:

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-4 = a(0)* +b(0)+c c = -4

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Step 3

Now, put the remaining points in the equation y=ax...

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-6 = a(2)' + b(2)–4 .(1) 4a + 2b = -2 Now, put (-3,-31): -31 = a(-3)' +b(-3)– 4 9a – 3b = -27 За -b %3D —9 (2)

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