For Exercise, solve for the indicated variable. for r > 0

Q: The formula occurs in the indicated application. Solve for the specified variable.

A: R=VI

Q: Using the given diagram, solve for x. 4 22 X X=

A:

Q: Given f(x) = ar² + 2x and f'(1) = 5, solve for a.

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Q: Solve the formula for the specific variable. FK + M = D -UK  for K

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Q: For Exercise, solve for the indicated variable. -E for k (used in chemistry) LA- In RT

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Q: Solve for the specified variable : T = (A - P) / Pr for P

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Q: Solve  formula for the specified variable.C = 2π r for r

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Q: From the table below, find Bo , B, & show the best equation of the linear n estimate amount (Y) if…

A: Excel Procedure: Enter X and Y in Excel>Data>Data Analysis> ‘Regression’>Select Y under…

Q: Describe verbally how to solve y=mx+c.  What assumptions have you made about the value of m?

A: To Describe verbally how to solve y=mx+c.  What assumptions have you made about the value of m?

Q: Solve the equation for the indicated variable.

A: a2x+a-1=a+1x

Q: The formula occurs in the indicated application. Solve for the specified variable.

A: we have been given a formula we have to solve for the specified variable. here C=2πr we have to…

Q: Solve the  formula for the indicated variable. Mechanics v = - gt + v0 for t

A: To Solve the  formula for the indicated variable: v=-gt+v0,for t. Solution: v=-gt+v0On simplifying…

Q: Solve for the following equationfor x. 1. l 5x + 2 l = l 3x - 2 l

A: Given: 5x+2=3x-2 ⇒5x+2=±3x-2

Q: The formula occurs in the indicated application. Solve for the specified variable.

A: We have given a formula A=P+Prt and we have asked to solve for r.

Q: Given h(x) = -x - 3, solve for a when h( = -10.

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Q: Solve the following equation for r. M=-Try

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Q: Given h(x) = 2x 3, solve for a when h(a) =-3.

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Q: Solve the equation for the unknown quantity x. 12 X = 42 %3D 0.66 1.5 1 2.26

A: Given equation is  12x=42

Q: For Exercise, solve for the indicated variable. for g T = 27,

A: To solve the given equation for the indicated variable.

Q: В. Solve for the value of x. 1. 2. S x-1 12 B.

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Q: For Exercise, solve for the indicated variable. P = -Lm for L 3

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Q: Given the figure below, solve for the value of x. 250°

A: Given that:Measure of arc LBP = 250° (Right side)

Q: 1. 9 m 60

A:

Q: Solve the following formula for the indicated variable. solve for y. 3y - x

A: We can find the formula for y by rearranging the terms of the given equation.

Q: Given h(x) = -3x - 2, solve for a when h(x) = 1.

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Q: Solve the equation for the indicated variable.

A: Given V=13πr2h

Q: Given h(x) = -x - 4, solve for x when h(x) = 9.

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Q: ab=c for b          i dont know how to solve this for indicated variables

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Q: Given f(x)=250 e0.07x , solve f'(x)=130

A: The derivative for the function is calculated.

Q: For Exercise, solve for the indicated variable. A = P(1 + r)t for t.

A: Given:

Q: Solve for the specified variable.  V = 1/3 Ah for h

A: Move all the variables on the right hand side and the variable h on the left hand side.

Q: 8+t+6t² –12t³ dt Evaluate (3r² +4)(r² +7) 2

A: Given that: ∫8+t+6t2-12t3(3t2+4)(t2+7)dt

Q: solve for t ?

A:

Q: For Exercise, solve the equation. In x + 3VIn x – 10 = 0

A: Given: Equation To Find: Value of x Calculation: Let ln(x) = u The given equation turns to:

Q: Solve for y. x+y=6 x=2 Simplify your answer as much as possible. = 0 믐 마음 v =

A: Put value of x in equation to find value of y.

Q: Use the One-to-One Property to solve the following equation for x. Sx-1 = 27 1 3 8

A:

Q: The formula occurs in the indicated application. Solve for the specified variable.

A: the given formula is: S=pq+p1-q we have to solve for the variable q.

Q: Given the formula below, solve for x. y - 9, = m(s - 1) m(g – 1) OA OB. - 31 - 1 OD. 11 + 51

A: Given formula is: y-y1=mx-x1 We have to solve for x.

Q: For Exercise, solve for the indicated variable. A = for t

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Q: Solve the formula for x. Mx + Ny = P X=

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Q: For Exercise, solve for the indicated variable. kF for m т

A: To solve the below equation for m

Q: Solve for the specified variable,  L=E (Ar + n), for A

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Q: For Exercise, solve for the indicated variable. |2s for s t =

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Q: The formula occurs in the indicated application. Solve for the specified variable.

A: F=gmMd2

Q: For Exercise, solve for the indicated variable. V =-arh for h 3

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Q: For Exercise, find the real solutions to the equation.  x2e^x−e^x = 0

A: Consider the provided equation,

Q: HW. Similarly solve x=fl =47

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Q: Using the given diagram, solve for x.

A: we have to use Angle bisector theorem

Q: Given the figure below, solve for x. Then, find the value of QP.

A: Q and P are the midpoint of HI  and HG QP is parallel to IG Length of middle line = half of the base…

Q: Solve the equation Utt + uraxa = 0, -000 u(x, 0) = f(x), ut(x,0)=0 for -00 <x<0o.

A: