For Exercise, solve the equation. x+1 72r-3 = 49

Q: For Exercise, solve the equation. 4 = 3 + 3(x + 1)

A: Given:

Q: For Exercise, solve the equation. 2 3 15

A:

Q: For Exercise, solve the equation. 113c+1

A:

Q: For Exercise, make an appropriate substitution and solve the equation. 4 + 1 = 0 -- х

A:

Q: For Exercise, solve the equation. 2 (x + 1) + 10 ||

A: The given equation is

Q: Solve the equation:Vx + 47 = x + 5 %3| Answer: x ||

A: Given: The equation x+47=x+5 To find: The value of x which satisfies the given equation.

Q: Solve the equation. e4x+4e2x-21=0

A: Let us suppose y = e2x, substitute the value of y in the given equation:

Q: For Exercise, solve the equation. 3x = 81

A: Given,

Q: For Exercise, solve the equation. (x2− 4)2 − 7(x2 − 4) − 60 = 0

A: Given:

Q: For Exercise, solve the equation. 10w2/3 10

A: To solve the given equation.

Q: For Exercise, solve the equation. -2V3m + 4 – 3 = 5

A:

Q: For Exercise, make an appropriate substitution and solve the equation. (++2) - 12(*+9)* + 35 = 0

A: Substitute and solve for y:

Q: For Exercise, solve the equation. 50e2x+1 = 2000

A: Given: The equation

Q: For Exercise, solve the equation. 6 = 9 + V5 – 3x

A:

Q: For Exercise, solve the equation. V3x + 1 = 11

A:

Q: Solve the equation. e4x + 4e2x - 21 = 0

A: A quadratic equation of the form x2+ax+bx+ab can be factored as (x+a)(x+b). For a factored quadratic…

Q: For Exercise, solve the equation. 4 -2 5z - 3 4z + 7

A:

Q: For Exercise, solve the equation. + 1 4 10

A: Given,

Q: Bu R(w)

A: Note: Here we are solving problem a) for problem b) please submit the que again. Given: Rw=4-3ww+2…

Q: Solve the equation. e2x - ex - 6 = 0

A:

Q: For Exercise, solve the equation. x + 1) - 2 3" 1) –

A: Given expression

Q: Solve the equation -3X + A = B for X, given that and B = [ 2 -5 –1

A:

Q: For Exercise, solve the equation. 36d -2 − 5d -1 − 1 = 0

A: Given,

Q: For Exercise, solve the equation. x + 3 :- 4 + 2 = 5х х

A: LCM of the denominators is =5x So to get rid of the fractions we multiply both sides by 5x.

Q: For Exercise, solve the equations. -w 2 3 2

A: Add 1/3 to both sides

Q: For Exercise, use A = -4 and solve for X 4 and B = -2. [6 A + 5X = B

A:

Q: For Exercise, solve the equation. Va + 18 + 2 = a

A:

Q: For Exercise, solve the equation. 5m 3 т — 1 т + Зт — 4 т+4

A: Given,

Q: For Exercise, solve the equation. V1 + Vx + Vx + 1 = 2

A:

Q: For Exercise, use A = and B = -4 -4 and solve for X. 6. 2A - B = 10X

A:

Q: For Exercise, solve the equation. т 2 + 1 2m + 1 т — 3

A: Given equation

Q: For Exercise, solve the equation. z + 5 5z + 3 20 4

A:

Q: For Exercise, solve the equation. 5 -2 2n + 1 Зл — 4

A: To solve the given equation.

Q: Solve the equation for r, substitute 8 for h. 0=2πr2+2πrh=2πr2+16πr

A: Given equations is                                              2πr2+2πrh=2πr2+16πr=0; h=8

Q: Solve the equation and check. 15(x + 3) = 9(x - 5) – 8(x + 4) - 4 X =

A:

Q: Solve the equation3(X - 4) +2 X = 5 ( X + 3) - 27

A: given that     3(X - 4) +2 X = 5 ( X + 3) - 27

Q: For Exercise, solve the equation. V2t + 8 – t= 4

A: Given equation:

Q: Use the One-to-One Property to solve the equation for x. ex2-4  = e3x ​

A: Refer to the question,According to one to one property of exponents if bases are same, af(x) =…

Q: For Exercise, solve for the indicated variable. 3x− y= −8 for x

A:

Q: r 4) V3r- 200

A:

Q: For Exercise, solve the equation. 5y – 3 – 2y + 1 = 0]

A: Add 4th root of (2y+1) with both sides.

Q: For Exercise, solve for the indicated variable. 2a + 2b? – 2c² for a >0

A:

Q: For Exercise, solve the equation. 0.65(x − 6) + 0.35(x + 4) = 0.5

A:

Q: x²y' +x³y²e* = -xy

A: x2y'+x3y2ex=−xyx2y'+xy=−x3y2exx2y'+1xy=−x3y2exy'+1xy=−xexy2

Q: For Exercise, solve for the indicated variable. 3 -m' for m, m > 0

A: Given that, Q=34m3           ...(1)

Q: For Exercise, make an appropriate substitution and solve the equation. 3 -4 (т — 3) 3 т

A:

Q: x? - y? Solve y' with y(1) = 2. ху

A:

Q: Solve the equation4 ( X - 2) + X = 5 ( X - 3) + 7

A: given that         4 ( X - 2) + X = 5 ( X - 3) + 7

Q: For Exercise, solve the equation. 4v 10 = v + 5v – 25

A:

Q: For Exercise, solve the equation. т + 2 т — 4 т+1 4

A: The given expression is