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Asked Dec 25, 2019
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For Exercise, solve the system of nonlinear equations.

(y-2)=-8(x-1)

2x-y=-8

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The given system of equations is (y– 2) = -8(x– 1) and 2x- y= -8. Rewrite the equation 2x – y=-8 as y= 2x +8 and substitute y= 2x+8 in (y- 2) = -8(x–1). (y- 2) = -8(x-1) (2x+ 6)' =-8x+8 4x + 2. 2x. 6+36 = -8x+8 4x + 24x + 36 +8x – 8 = 0 4x +32x + 28=0

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