(If possible could you please type out the steps? thankyou!) 18. 95 = -4(m – 3)² – 5Mary95 = -4(m - 3)2 - 5+5+5100 = -4(m - 3)²± V100 = -2(m – 3)± 10 = -2(m - 3)|%3D10%3D -2(т — 3) -103 -2(т - 3)10= m - 3-2-10= m – 3-2-5 = m - 35 = m – 3-2= m8 = m| For Exercises 17 and 18, the students were asked to solvethe given equation using the square root property. Explainwhat the student did wrong. Give the correct answer.

The given equation is. 95=-4(m-3)2-5 ⇒100=-4(m-3)2 ....(1)…

Answered: 18. 95 = -4(m – 3)² – 5 %3D | Мary 95 =…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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18. 95 = -4(m – 3)² – 5 %3D | Мary 95 = -4(m - 3)² – 5 +5 +5 100%3D - 4(т - 3)° + V100 = -2(m – 3) + 10 = -2(m – 3) | | 10 = -2(m – 3) -10 = - 2(m – 3) - 3) | 10 = m - 3 -2 -10 - — т — 3 -2 | | -5 = m - 3 5%3D т — 3 | -2 = m 8 = m